Write a regular expression that matches any string that starts with one or more ‘1’s, followed by three or more ‘0’s, followed by any number of ones (zero or more), followed by ‘0’s (from one to seven), and then ends with either two or three ‘1’s.
code snippet:Test case-1;
string = '11000011000111'
Test case-2:
string = '00001100011111'
# regex pattern
#pattern = '^1{1, }0{3, }1{0, }0{1,7}1(2|3)$'
pattern = '^1+0{3,}1*0{1,7}1{2,3}$'
# check whether pattern is present in string or not
result = re.search(pattern, string)
# evaluate result
if result != None:
print(True)
else:
print(False)
Explanation:
The ‘^’ specifies the start of the string.
‘$’ specifies the end of the string.
|- Means OR (Matches with any of the characters separated by it.
|- Means OR (Matches with any of the characters separated by it.
* -Any number of occurrences (including 0 occurrences)
+ - One or more occurrences
{} - Indicate number of occurrences of a preceding RE
to match.
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